(x^2+1)(x-3)=0

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Solution for (x^2+1)(x-3)=0 equation: 


Simplifying
(x2 + 1)(x + -3) = 0

Reorder the terms:
(1 + x2)(x + -3) = 0

Reorder the terms:
(1 + x2)(-3 + x) = 0

Multiply (1 + x2) * (-3 + x)
(1(-3 + x) + x2(-3 + x)) = 0
((-3 * 1 + x * 1) + x2(-3 + x)) = 0
((-3 + 1x) + x2(-3 + x)) = 0
(-3 + 1x + (-3 * x2 + x * x2)) = 0
(-3 + 1x + (-3x2 + x3)) = 0
(-3 + 1x + -3x2 + x3) = 0

Solving
-3 + 1x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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